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bypass ssl security while fetching invalid https url

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This commit is contained in:
Carl Chenet 2019-12-25 23:27:44 +01:00
parent bae51858e6
commit 15415e369a
6 changed files with 54 additions and 4 deletions
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7
feed2toot/confparsers/rss/uri.py
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@ -18,10 +18,11 @@
# standard library imports
import feedparser
import ssl
import sys
import re
def parseuri(config, clioption, feeds):
def parseuri(config, clioption, feeds, ignoressl):
'''Parse configuration value of the uri option of the rss section'''
rssuri = ''
feedname =''
@ -48,6 +49,10 @@ def parseuri(config, clioption, feeds):
sys.exit('{confoption} parameter in the [{section}] section of the configuration file is mandatory. Exiting.'.format(section=section, confoption=confoption))
else:
rssuri = clioption
# ignore ssl if asked
if ignoressl:
if hasattr(ssl, '_create_unverified_context'):
ssl._create_default_https_context = ssl._create_unverified_context
# get the rss feed for rss parameter of [rss] section
feed = feedparser.parse(rssuri)
if not feed: